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8d^2-22d+9=0
a = 8; b = -22; c = +9;
Δ = b2-4ac
Δ = -222-4·8·9
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14}{2*8}=\frac{8}{16} =1/2 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14}{2*8}=\frac{36}{16} =2+1/4 $
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